4x^2-25/2x-5=14

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Solution for 4x^2-25/2x-5=14 equation:


x in (-oo:+oo)

4*x^2-((25/2)*x)-5 = 14 // - 14

4*x^2-((25/2)*x)-14-5 = 0

4*x^2+(-25/2)*x-14-5 = 0

4*x^2-25/2*x-19 = 0

DELTA = (-25/2)^2-(-19*4*4)

DELTA = 1841/4

DELTA > 0

x = ((1841/4)^(1/2)+25/2)/(2*4) or x = (25/2-(1841/4)^(1/2))/(2*4)

x = ((1841/4)^(1/2)+25/2)/8 or x = (25/2-(1841/4)^(1/2))/8

x in { (25/2-(1841/4)^(1/2))/8, ((1841/4)^(1/2)+25/2)/8 }

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